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How do you balance this chemical equation: $H I (g) \to H_{2} (g) + I_{2} (g)$ $HI(g) → H_2(g) + I_2(g)$ ?

1 Answer

May 22, 2016

$\frac{1}{2} I_{2} (g) + \frac{1}{2} H_{2} (g) ⇌ H I (g)$ $1/2I_2(g) + 1/2H_2(g) rightleftharpoonsHI(g)$

Explanation:

How could I remove the $\frac{1}{2}$ $1/2$ coefficient?

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