How do you balance this equation? MnO_2 + Al -> Mn + Al_2O_3MnO2+AlMn+Al2O3

1 Answer
Jul 7, 2016

3MnO_2+4Al -> 3Mn+2Al_2O_33MnO2+4Al3Mn+2Al2O3

Explanation:

Since we have a multiple of 33 oxygens on the right hand side we require a multiplier of 33 on the left hand side.

If we have 3MnO_23MnO2 on the left hand side, then that is a total of 33 manganeses and 66 oxygens, requiring 3Mn+2Al_2O_33Mn+2Al2O3 on the right hand side.

Then we need 44 aluminiums on the left hand side.

Hence the balanced form of the equation is:

3MnO_2+4Al -> 3Mn+2Al_2O_33MnO2+4Al3Mn+2Al2O3