How do you balance $Z n + C u S O_{4} \to Z n S O_{4} + C u$ $Zn + CuSO_4 -> ZnSO_4 + Cu$ ?

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How do you balance $Z n + C u S O_{4} \to Z n S O_{4} + C u$ $Zn + CuSO_4 -> ZnSO_4 + Cu$ ?

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Answer 1 · 2017-08-21T14:45:52

It is already balanced.

Explanation:

What I always do first when balancing chemical equations is calculating the number of atoms for each element :

Zinc (Zn), we have $1$ $1$ on the LHS, and $1$ $1$ on the RHS.
Copper (Cu), we have $1$ $1$ on the LHS, and $1$ $1$ on the RHS.
Sulphur (S), we have $1$ $1$ on the LHS, and $1$ $1$ on the RHS.
Oxygen (O), we have $4$ $4$ on the LHS, and $4$ $4$ on the RHS.

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How do you balance $Z n + C u S O_{4} \to Z n S O_{4} + C u$ $Zn + CuSO_4 -> ZnSO_4 + Cu$ ?

1 Answer

Explanation:

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Math

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How do you balance Zn+CuSO4→ZnSO4+CuZn + CuSO_4 -> ZnSO_4 + Cu?

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Explanation:

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How do you balance $Z n + C u S O_{4} \to Z n S O_{4} + C u$ $Zn + CuSO_4 -> ZnSO_4 + Cu$ ?