Question

How do you calculate `antilog (0.6117 + -3)`?

Answer 1

`x=0.0040898`

Explanation:

Let `x=anti log(0.6117+(-3))`

then `0.6117+(-3)=logx`

or `0.6117=logx+3=log(1000x)`

and `1000x=anti log(0.6117)`

from tables, `antilog0.6117=4.0898`

and `x=0.0040898`