How do you calculate $a r c cot (tan (\frac{79 π}{180}))$ $arc cot(tan ((79pi)/180))$ ?

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Answer 1 · 2016-05-20T14:59:05

$(\frac{11}{180}) π$ $(11/180)pi$ , radian.

$tan (\frac{79 π}{180}) = cot (\frac{π}{2} - \frac{79 π}{180}) = cot (\frac{11 π}{180})$ $tan ((79pi)/180)= cot (pi/2-(79pi)/180)=cot((11pi)/180)$

Use $a r c cot (cot a) = a$ $arc cot (cot a)=a$

Here, the given expression is $a r c cot (\frac{11 π}{180}) = (\frac{11}{180}) π$ $arc cot ((11pi)/180)=(11/180)pi$ .

How do you calculate arccot(tan(79π180))arc cot(tan ((79pi)/180))?