Question

How do you calculate `cos^-1(sqrt3/2)`?

Answer 1

`x=pi/6`

Explanation:

`cos^-1(sqrt3/2)=x hArr cosx=sqrt3/2`, from the definition of the inverse function.

Now, we know for `cosx=sqrt3/2, x=pi/6+2npi, x=(11pi)/6+2npi` are valid solutions; however, since the domain of the arccosine is `[-1, 1], x=pi/6` is the only solution.