Question

How do you calculate `log _6 (1)`?

Answer 1

`log_6(1)=color(green)(0)`

Explanation:

Remember what `log` actually means:
`color(white)("XXX")log_b(a)=color(red)(c)` means `b^color(red)(c)=a`

In the given case
`color(white)("XXX")`if `log_6(1)=color(red)(c)` this means that `6^color(red)(c)=1`

...and since `6^color(red)(0) =1`

`log_6(1)=color(red)(0)`