How do you calculate #Log_7 (42 )#?

Question

2220 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-20T08:36:19

#color(pink)(=> 1.9208#

#log_7 42#

As per base change rule,

#log_b a = log_c a / log_c b#

#log_7 42 = log_(10) 42 / log_(10) 7#

#log (mn) = log m + log n#

#:. => (log 7 + log 6) / log 7#

#=> log 7 / log 7 + log 6 / log 7#

}=> 1 + log 6 / log 7#

#=> 1 + (0.7782) / (0.8451)#

#color(pink)(=> 1.9208#