How do you calculate $sin {(\frac{1}{2}) arccos (\frac{4}{5})}$ $sin{(1/2) arccos (4/5)}$ ?

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How do you calculate $sin {(\frac{1}{2}) arccos (\frac{4}{5})}$ $sin{(1/2) arccos (4/5)}$ ?

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Answer 1 · 2015-11-04T16:38:40

Calculate $sin {(\frac{1}{2}) arccos (\frac{4}{5})]$ $sin {(1/2)arccos (4/5)]$

Ans: $\pm 0.32$ $+- 0.32$

Explanation:

Use calculator.
$cos x = \frac{4}{5} = 0.8$ $cos x = 4/5 = 0.8$ --> arc $x = \pm 36^{\circ} 87$ $x = +- 36^@87$
Arc $\frac{x}{2} = \pm 18^{\circ} 43$ $x/2 = +- 18^@43$ .
$sin (\pm 18.43) = \pm 0.32$ $sin (+-18.43) = +- 0.32$

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How do you calculate $sin {(\frac{1}{2}) arccos (\frac{4}{5})}$ $sin{(1/2) arccos (4/5)}$ ?

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