How do you calculate #sum_(n=1)^(∞)(4/3)^(2-n)#?
How do you calculate #sum_(n=1)^(∞)(4/3)^(2-n)# ?
How do you calculate
2 Answers
Explanation:
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First term
Second Term (
Third term
Fourth Term
Fifth term
As can be seen, the first five terms of this series are:
This is a geometric series with a common ratio of
If
Explanation:
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