How do you calculate $[{tan}^{- 1} ((\frac{1}{2}))]$ $[tan^-1((1/2))]$ ?

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How do you calculate $[{tan}^{- 1} ((\frac{1}{2}))]$ $[tan^-1((1/2))]$ ?

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Answer 1 · 2017-02-17T01:07:29

$26^{\circ} 57 + k 180^{\circ}$ $26^@57 + k180^@$

Explanation:

Find $arctan (\frac{1}{2})$ $arctan (1/2)$ .
Calculator -->
$tan x = \frac{1}{2}$ $tan x = 1/2$ --> arc $x = 26^{\circ} 57 + k 180^{\circ}$ $x = 26^@57 + k180^@$

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How do you calculate $[{tan}^{- 1} ((\frac{1}{2}))]$ $[tan^-1((1/2))]$ ?

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