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How do you calculate ${tan}^{- 1} (- \sqrt{3})$ $tan ^-1 (- sqrt 3)$ ?

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Konstantinos Michailidis

May 18, 2016

Set $x = {tan}^{- 1} (- \sqrt{3})$ $x=tan^-1(-sqrt3)$ hence $tan x = - \sqrt{3}$ $tanx=-sqrt3$

The angle we are looking for is $x = - \frac{π}{3}$ $x=-pi/3$

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