How do you calculate the derivative for $g(t)= 7/sqrtt$ ?

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Answer 1 · 2015-03-29T21:37:12

You can rewrite the equation $g(t)=7*t^(-1/2)$

Minus because it's under the bar, 1/2 because it's a square root.

Then it's the recipe: one off the power, multiply by the power:

$g'(t)=7*(-1/2)*t^(-1 1/2)=7/(2*t sqrtt$

How do you calculate the derivative for g(t)= 7/sqrttg(t)= 7/sqrtt?