Question

How do you calculate the inverse sin(-7/3)?

Answer 1

There is no such thing. (There is no real number whose sine is `-7/3`.)

Explanation:

`y=arcsin(x)` if and only if `sin(y)=x` and `-pi/2 <= y <= pi/2`

For any real `y`, we have `-1 <= siny <= 1`.

Since `-7/3 < -1`, there is no real `y` with `sin(y) = -7/3`.