How do you calculate the mass of $3.24x10^18$ atoms of iron?

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Answer 1 · 2016-09-10T21:37:11

Less than a milligram of iron.

It is a fact that $"Avogadro's number"$ of iron atoms have a mass of $55.85*g$ .

Since $"Avogadro's number"$ $=$ $6.022xx10^23$ , mass of iron, $=$ $55.85*gxx(3.24xx10^18)/(6.022xx10^23)$ $=$ $3xx10^-4*g$ .

How do you calculate the mass of 3.24x10^183.24x10^18 atoms of iron?