How do you calculate the mass percentage of different constituent elements in urea?

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How do you calculate the mass percentage of different constituent elements in urea?

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Answer 1 · 2016-09-08T08:53:06

$% element$ $"% element"$ $=$ $=$ $\frac{Mass of element}{Molar mass of element} \times 100 %$ $"Mass of element"/"Molar mass of element"xx100%$

Explanation:

For urea, $C O {(N H_{2})}_{2}$ $CO(NH_2)_2$ , the molar mass is $60.06 \cdot g \cdot m o l^{- 1}$ $60.06*g*mol^-1$ .

And thus $% nitrogen$ $"% nitrogen"$

$=$ $=$ $\frac{2 \times 14.01 \cdot g \cdot m o l^{- 1}}{60.06 \cdot g \cdot m o l^{- 1}} \times 100 % = 46.6 %$ $(2xx14.01*g*mol^-1)/(60.06*g*mol^-1)xx100%=46.6%$

$% oxygen$ $"% oxygen"$ $=$ $=$ $? ?$ $??$

$% hydrogen$ $"% hydrogen"$ $=$ $=$ $? ?$ $??$

You will know if you are right if all the percentages add up to $100 %$ $100%$ . Why should this be so?

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How do you calculate the mass percentage of different constituent elements in urea?

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