How do you calculate the pH of 0.075M KOH?

1 Answer
anor277
May 17, 2017

pH=12.88

Explanation:

We know (i) that pH+pOH=14 in aqueous solution under standard conditions...........

We also know (ii) that pOH=-log_10[HO^-]

=-log_10(0.075)=-(-1.12)=+1.12.

And so pH=14-pOH=12.88

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