How do you calculate the $sin ({sin}^{- 1} (\frac{1}{3}))$ $sin(sin^-1 (1/3))$ ?

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How do you calculate the $sin ({sin}^{- 1} (\frac{1}{3}))$ $sin(sin^-1 (1/3))$ ?

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Answer 1 · 2015-11-21T00:39:19

$sin ({sin}^{- 1} (\frac{1}{3}))$ $sin(sin^-1(1/3))$ $=$ $=$ $\frac{1}{3}$ $1/3$

Explanation:

You can just use B.E.D.M.A.S to evaluate this equation, by doing ${sin}^{- 1} (\frac{1}{3})$ $sin^-1(1/3)$ , you get $\approx 19.47$ $~~19.47$ .
Then take the $sin$ $sin$ of $19.47$ $19.47$ which ultimately gives you the same thing back. $\frac{1}{3}$ $1/3$

Answer 2 · 2015-11-21T00:42:06

$\frac{1}{3}$ $1/3$

Explanation:

$\frac{1}{x} \cdot x = 1$ $1/x*x=1$

$x - x = 0$ $x-x=0$

$\sqrt{x^{2}} = x$ $sqrt(x^2)=x$

$10^{log x} = x$ $10^(logx)=x$

All of these are examples of functions and identities that undo one another. Another example of similar functions are $sin$ $sin$ and ${sin}^{- 1}$ $sin^-1$ .

$sin ({sin}^{- 1} (x)) = x$ $sin(sin^-1(x))=x$

$sin ({sin}^{- 1} (\frac{1}{3})) = \frac{1}{3}$ $sin(sin^-1(1/3))=1/3$

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How do you calculate the $sin ({sin}^{- 1} (\frac{1}{3}))$ $sin(sin^-1 (1/3))$ ?

2 Answers

Explanation:

Explanation:

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