Question

How do you calculate the `tan(sin^-1(0))`?

Answer 1

`0`

Explanation:

A way to interpret this is to ask yourself the following:

When `sinx=0`, what's `tanx`?

`sinx=0` at `0,pi`.

However, you must know the domain of the function `sin^-1(x)` is `-pi/2 < x < pi/2`, so only `0` applies.

Now, we know that `sin^-1(0)` is `0`, so we evaluate `tan0` to once again receive an answer of `0`.