How do you calculate the $tan(sin^-1(0))$ ?

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Answer 1 · 2015-11-21T15:26:32

$0$

A way to interpret this is to ask yourself the following:

When $sinx=0$ , what's $tanx$ ?

$sinx=0$ at $0,pi$ .

However, you must know the domain of the function $sin^-1(x)$ is $-pi/2 < x < pi/2$ , so only $0$ applies.

Now, we know that $sin^-1(0)$ is $0$ , so we evaluate $tan0$ to once again receive an answer of $0$ .

How do you calculate the tan(sin^-1(0))tan(sin^-1(0))?