How do you calculate the volume of 66.5 g of carbon monoxide at STP?

1 Answer
Jul 3, 2018

Volume=53.2dm3

Explanation:

Well simple comparison method..

COSTP

Molar mass ofxCO=12+16=28gmol1

Let the volume be represented as x

Therefore;

28gmol122.4moldm3

66.5gxdm3

Cross multiplying;

28×x=22.4×66.5

28x=1489.6

x=1489.628

x=53.2dm3