How do you calculate the volume of 66.5 g of carbon monoxide at STP?

1 Answer
Jul 3, 2018

"Volume" = 53.2dm^3

Explanation:

Well simple comparison method..

CO rarr STP

"Molar mass of" color(white)xCO = 12 + 16 = 28gmol^-1

Let the volume be represented as x

Therefore;

28gmol^-1 rarr 22.4moldm^-3

66.5g rarr xdm^3

Cross multiplying;

28 xx x = 22.4 xx 66.5

28x = 1489.6

x = 1489.6/28

x = 53.2dm^3