How do you change a standard form equation into slope-intercept form for $2 x + 4 y = 17$ $2x+4y=17$ ?

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How do you change a standard form equation into slope-intercept form for $2 x + 4 y = 17$ $2x+4y=17$ ?

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Answer 1 · 2015-03-31T12:37:55

By simply rearranging your equation to isolate $y$ $y$ :
getting: $y = - \frac{2}{4} x + \frac{17}{4}$ $y=-2/4x+17/4$ I took $2 x$ $2x$ to the right (changing sign) and divided everything by the coeficiente of $y$ $y$ ;
so:
$y = - \frac{1}{2} x + \frac{17}{4}$ $y=-1/2x+17/4$
and:
slope= $- \frac{1}{2}$ $-1/2$
intercept= $\frac{17}{4}$ $17/4$

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How do you change a standard form equation into slope-intercept form for $2 x + 4 y = 17$ $2x+4y=17$ ?

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How do you change a standard form equation into slope-intercept form for 2x+4y=172x+4y=172x+4y=17?

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How do you change a standard form equation into slope-intercept form for $2 x + 4 y = 17$ $2x+4y=17$ ?