How do you combine #sqrt80+sqrt45-sqrt20#?

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Answer 1 · 2018-04-29T22:05:42

#5sqrt5#

#sqrt80 + sqrt45 - sqrt20#

Simplify:
#sqrt(16 * 5) + sqrt(9 * 5) - sqrt(4 * 5)#

#sqrt16 * sqrt5 + sqrt9 * sqrt5 - sqrt4 * sqrt5#

#4 * sqrt5 + 3 * sqrt5 - 2 * sqrt5#

#4sqrt5 + 3sqrt5 - 2sqrt5#

Since the value inside each of the square root signs are the same, that means we can do: #4 + 3 - 2#, which equals #5#

Therefore the answer is:
#5sqrt5#

Hope this helps!