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How do you complete the ordered pairs so that each ordered pair satisfies the given equation (3, a), (b, -1), 4x - 3y = 7?

1 Answer

Oct 6, 2015

$(3, a) = (3, \frac{5}{3})$ $(3,color(red)(a)) = (3,color(red)(5/3))$
and $(b, - 1) = (1, - 1)$ $(color(blue)(b),-1)=(color(blue)(1),-1)$

Explanation:

Given $4 x - 3 y = 7$ $4x-3y=7$

Point 1
If $(x, y) = (3, a)$ $(x,y) = (3,a)$
$XXX 4 (3) - 3 (a) = 7$ $color(white)("XXX")4(3)-3(a)=7$

$XXX \to 12 - 3 a = 7$ $color(white)("XXX")rarr 12-3a=7$

$XXX \to - 3 a = - 5$ $color(white)("XXX")rarr -3a= -5$

$XXX \to a = \frac{5}{3}$ $color(white)("XXX")rarr a = 5/3$

Point 2
if $(x, y) = (b, - 1)$ $(x,y)= (b,-1)$
$XXX 4 (b) - 3 (- 1) = 7$ $color(white)("XXX")4(b)-3(-1)=7$

$XXX \to 4 b + 3 = 7$ $color(white)("XXX")rarr 4b+3=7$

$XXX \to 4 b = 4$ $color(white)("XXX")rarr 4b=4$

$XXX \to b = 1$ $color(white)("XXX")rarr b=1$

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