How do you compute #50-82#?

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Answer 1 · 2016-11-04T09:14:38

#-32#

use the relationship

#a-b=-(b-a)#

#50-82=-(82-50)#

#=-32#

In other words if the first number #># the second number .

Subtract the other way round and put a #-# in front of the answer.

Answer 2 · 2016-11-05T15:58:05

Just for fun this is another approach

#-32#

50 is another way of writing #82-32#

So instead of writing 50 write #82-32# giving

#color(blue)(color(magenta)(50) -82" "->" "color(magenta)(cancel(82)-32)-cancel(82))" "=-32#