How do you compute the value of #int 1/x dx# of #[1,10]#? Calculus Introduction to Integration Definite and indefinite integrals 1 Answer Andrea S. Nov 24, 2016 Using the fundamental theorem of Calculus Explanation: #int_a^b f(x)dx = F(b) - F(a)# where #(dF(x))/dx = f(x)# As: #int_1^"10"1/x dx = int_1^"10" d((ln(x)))/dx = ln(x) |_1^"10"= ln(10) -ln(1) = ln(10)# Answer link Related questions What is the difference between definite and indefinite integrals? What is the integral of #ln(7x)#? Is f(x)=x^3 the only possible antiderivative of f(x)=3x^2? If not, why not? How do you find the integral of #x^2-6x+5# from the interval [0,3]? What is a double integral? What is an iterated integral? How do you evaluate the integral #1/(sqrt(49-x^2))# from 0 to #7sqrt(3/2)#? How do you integrate #f(x)=intsin(e^t)dt# between 4 to #x^2#? How do you determine the indefinite integrals? How do you integrate #x^2sqrt(x^(4)+5)#? See all questions in Definite and indefinite integrals Impact of this question 1164 views around the world You can reuse this answer Creative Commons License