Question

How do you condense `7lnx-2lny`?

Answer 1

`ln(x^7/y^2)`

Explanation:

We may use the identities `lna-lnb=ln(a/b)` and `alnb=lna^b`.

Using them `7lnx-2lny`

= `lnx^7-lny^2`

= `ln(x^7/y^2)`