Question

How do you condense `ln(1+x^9)+1/2(ln(x)-ln(sin(x)`?

Answer 1

`ln(1+x^9)+1/2lnx-ln(sinx)=(1+x^9)/(2sinx)`

Explanation:

Use the following 2 laws of logs :

`logAB=logA+logB`

`log(A/B)=logA-logB`

to get :

`ln(1+x^9)+1/2lnx-ln(sinx)=(1/2(1+x^9))/sinx`