Question

How do you condense `log_3 (9x^4)-log_3(3x)^2`?

Answer 1

Start by expanding `log_3(3x)^2`

`log_3(3x)^2 = log_3(9x^2)`

`=>log_3(9x^4) - log_3(9x^2)`

`=> log_3((9x^4)/(9x^2))`

`=>log_3(x^2)`

Hopefully this helps!