How do you convert $(0, - 3)$ $(0, -3)$ to polar form?

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Answer 1 · 2016-03-14T05:25:15

$(0, - 3)$ $(0,-3)$ is $(3, \frac{3 π}{4})$ $(3,(3pi)/4)$ in polar coordinates

$(r, θ)$ $(r,theta)$ in polar coordinates is $(r cos θ, r sin θ)$ $(rcostheta,rsintheta)$ in rectangular coordinates and

$(x, y)$ $(x,y)$ in rectangular coordinates is $(\sqrt{x^{2} + y^{2}}, arctan (\frac{y}{x}))$ $(sqrt(x^2+y^2),arctan(y/x))$ in polar coordinates.

As such, $(0, - 3)$ $(0,-3)$ in rectangular coordinates will be

$(\sqrt{0^{2} + {(- 3)}^{2}}, arctan (\frac{- 3}{0}))$ $(sqrt(0^2+(-3)^2),arctan((-3)/0))$ or

$(3, \frac{3 π}{4})$ $(3,(3pi)/4)$ in polar coordinates.

How do you convert (0, -3)(0,−3)(0, -3) to polar form?