How do you convert $(0, 8)$ $(0, 8)$ to polar form?

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Answer 1 · 2016-05-03T09:06:56

Polar coordinates for Cartesian coordinates $(0, 8)$ $(0,8)$ are $(8, \frac{π}{2})$ $(8,pi/2)$

If $(x, y)$ $(x,y)$ in Cartesian form and $(r, θ)$ $(r,theta)$ is in polar form the relation between them is as follows:

$x = r cos θ$ $x=rcostheta$ , $y = r sin θ$ $y=rsintheta$ , $r^{2} = x^{2} + y^{2}$ $r^2=x^2+y^2$ and $tan θ = \frac{y}{x}$ $tantheta=y/x$

Here $x = 0$ $x=0$ and $y = 8$ $y=8$ , hence

$r^{2} = 0^{2} + 8^{2} = 0 + 64 = 64$ $r^2=0^2+8^2=0+64=64$ or $r = 8$ $r=8$

$cos θ = \frac{0}{8} = 0$ $costheta=0/8=0$ and $sin θ = \frac{8}{8} = 1$ $sintheta=8/8=1$

Hence $θ = \frac{π}{2}$ $theta=pi/2$

Hence polar coordinates for Cartesian coordinates $(0, 8)$ $(0,8)$ are $(8, \frac{π}{2})$ $(8,pi/2)$

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