How do you convert $(- 1, 5)$ $(−1, 5)$ into polar form?

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Answer 1 · 2018-07-09T06:38:15

$(r, θ) = (\sqrt{26}, {101.31}^{\circ})$ $color(purple)((r, theta) = (sqrt26, 101.31^@)$

$Conversion from rectangular to polar coordinates$ $"Conversion from rectangular to polar coordinates "$

$r = \sqrt{x^{2} + y^{2}}, θ = arctan (\frac{y}{x})$ $r = sqrt (x^2 + y^2), theta = arctan (y/x)$

$(x, y) = 9 - 1, 5)$ $(x,y) = 9-1,5)$

$r = ∣ ∣ \sqrt{- 1^{2} + 5^{2}} ∣ ∣ = \sqrt{26}$ $r = |sqrt(-1^2 + 5^2)| = sqrt26$

$θ = arctan (\frac{5}{- 1}) \approx {101.31}^{\circ}, as in II Quadrant$ $theta = arctan (5/-1) ~~ 101.31^@, " as in II Quadrant"$

How do you convert (−1, 5)(−1,5) (−1, 5) into polar form?