Question

How do you convert `(-13,12)` to polar form?

Answer 1

`sqrt 313 [cos (pi - arctan frac{12}{13}) + i sin (pi - arctan frac{12}{13})]`

Explanation:

`x = r cos t, y = r sin t`

`-13 = r cos t, 12 = r sin t`

`13^2 + 12^2 = r^2 = 313`

`tan t = -12/13`

`t = - arctan frac{12}{13} + pi`

`-13 + 12 i = r (cost + i sin t)`