Question

How do you convert `(-2, 2)` to polar form?

Answer 1

`(-2,2)` in polar form is `(2sqrt2,(3pi)/4)`

Explanation:

`(a,b)` in polar form is `(r,theta)` where `r=sqrt(a^2+b^2)` and `tantheta=b/a`

Hence `(-2,2)` in polar form is `(r,theta)` where

`r=sqrt((-2)^2+2^2)=sqrt(4+4)=sqrt8=2sqrt2` and

`tantheta=2/(-2)=-1=(3pi)/4`

Hence `(-2,2)` in polar form is `(2sqrt2,(3pi)/4)`