Question

How do you convert `(-2, -2sqrt3)` to polar form?

Answer 1

( 4, 4`pi`/3 )

Explanation:

( x, y ) = ( `-`2, `-`2`sqrt`3 )
r = `sqrt`(x^x + y^y).
cos `theta` = x/r and sin `theta` = y/r.
cos (`pi` + `theta`) = `-` cos `theta`.
sin (`pi` + `theta`) = `-` sin `theta`