Question

How do you convert `(-2, 2sqrt3)` to polar form?

Answer 1

In Polar form `(r,theta)` is `4,120^0`

Explanation:

Polar distance `r=sqrt((-2)^2+(2sqrt3)^2)=4`
`theta=tan^-1((2sqrt3)/-2)=tan^-1(- sqrt3) =120^0` since the point is on 2nd quadrant [Ans]