Question

How do you convert `(-2, 7pi/3)` to rectangular form?

Answer 1

`=x=-1and y= -sqrt3`

Explanation:

If Cartesian or rectangular coordinate of a point be (x,y)
and its polar polar coordinate be `(r,theta)`

then `x=rcostheta and y= rsintheta`
here `r=-2 and theta =7pi/3`
`:.`
`x=-2cos(7pi/3) and y= -2sin(7pi/3)`
`=x=-2cos(2pi+pi/3) and y= -2sin(2pi+pi/3)`
`=x=-2cos(pi/3) and y= -2sin(pi/3)`
`=x=-2*1/2and y= -2*sqrt3/2`
`=x=-1and y= -sqrt3`