How do you convert $(−2, −9)$ into polar form?

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Answer 1 · 2017-02-06T20:09:11

$sqrt 85 [cos (pi + arctan 4.5) + i sin (pi + arctan 4.5)]$

$-2 = r cos t, -9 = r sin t$

$tan t = 9/2$

$t = pi + arctan 4.5$
Where we add $pi$ because our point is at 3rd quadrant.

$2^2 + 9^2 = r^2 = 85$

How do you convert (−2, −9)(−2, −9) into polar form?