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How do you convert $2 x + 3 y = 6$ $2x + 3y = 6$ into polar form?

1 Answer

Feb 28, 2016

$r (2 cos (θ) + 3 sin (θ)) = 6$ $r(2cos(theta)+3sin(theta))=6$

Explanation:

In converting for rectangular to polar form:
$XXX x \to r \cdot cos (θ)$ $color(white)("XXX")x rarr r*cos(theta)$
$XXX y \to r \cdot sin (θ)$ $color(white)("XXX")y rarr r*sin(theta)$

So $2 x + 3 y = 6$ $2x+3y=6$

$\to 2 (r \cdot cos (θ)) + 3 (r \cdot sin (θ)) = 6$ $rarr 2(r*cos(theta))+3(r*sin(theta))=6$

$\to r (2 cos (θ) + 3 sin (θ)) = 6$ $rarr r(2cos(theta)+3sin(theta))=6$

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