How do you convert #2x-5y+6=0# into slope intercept form?

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Answer 1 · 2015-04-01T20:24:38

Answer : # y = 2/5x + 6/5#

The slope-intercept form equation is of the form:
# y = mx + c#

We need to arrange #2x - 5y + 6 = 0# in the form above, right?

Here we go,

# -5y + 6 = -2x#

By factoring #-5# on my left hand side,
# -5(y - 6/5) = -2x#

Dividing both sides by #-5#
#=> y - 6/5 = (-2x)/(-5)#

#=> y - 6/5 = 2/5(x)#

# y = 2/5x + 6/5#

and voila.