How do you convert $2 x - 5 y + 6 = 0$ $2x-5y+6=0$ into slope intercept form?

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Answer 1 · 2015-04-01T20:24:38

Answer : $y = \frac{2}{5} x + \frac{6}{5}$ $y = 2/5x + 6/5$

The slope-intercept form equation is of the form:
$y = m x + c$ $y = mx + c$

We need to arrange $2 x - 5 y + 6 = 0$ $2x - 5y + 6 = 0$ in the form above, right?

Here we go,

$- 5 y + 6 = - 2 x$ $-5y + 6 = -2x$

By factoring $- 5$ $-5$ on my left hand side,
$- 5 (y - \frac{6}{5}) = - 2 x$ $-5(y - 6/5) = -2x$

Dividing both sides by $- 5$ $-5$
$\Rightarrow y - \frac{6}{5} = \frac{- 2 x}{- 5}$ $=> y - 6/5 = (-2x)/(-5)$

$\Rightarrow y - \frac{6}{5} = \frac{2}{5} (x)$ $=> y - 6/5 = 2/5(x)$

$y = \frac{2}{5} x + \frac{6}{5}$ $y = 2/5x + 6/5$

and voila.

How do you convert 2x−5y+6=02x-5y+6=0 into slope intercept form?