How do you convert $(- 3, 3)$ $(-3, 3)$ to polar form?

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Answer 1 · 2016-06-26T14:57:45

$(3 \sqrt{2}, \frac{3 π}{4})$ $(3sqrt2, (3pi)/4)$

The given

$x = - 3$ $x=-3$ and $y = 3$ $y=3$

$r = \sqrt{x^{2} + y^{2}} = \sqrt{{(- 3)}^{2} + {(3)}^{2}} = \sqrt{9 (2)} = 3 \sqrt{2}$ $r=sqrt(x^2+y^2)=sqrt((-3)^2+(3)^2)=sqrt(9(2))=3sqrt2$

$θ = arctan (\frac{y}{x}) = arctan (\frac{3}{- 3}) = arctan (- 1) = \frac{3 π}{4}$ $theta=arctan(y/x)=arctan(3/(-3))=arctan(-1)=(3pi)/4$

God bless....I hope the explanation is useful.

How do you convert (-3, 3)(−3,3) (-3, 3) to polar form?