How do you convert $(3, - 3 \sqrt{3})$ $(3, -3sqrt3)$ to polar form?

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How do you convert $(3, - 3 \sqrt{3})$ $(3, -3sqrt3)$ to polar form?

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Answer 1 · 2016-05-03T10:30:43

In polar form $(6, - 60^{\circ})$ $( 6, -60^@)$

Explanation:

$r = \sqrt{(3^{2} + {(- 3 \sqrt{3})}^{2})}$ $r= sqrt ((3^2 +(-3sqrt3)^2)$ $= \sqrt{36} = 6$ $= sqrt 36 =6$ $θ = {tan}^{- 1} (\frac{- 3 \sqrt{3}}{3}) = {tan}^{- 1} (- \sqrt{3}) = - 60^{\circ}$ $theta= tan^-1((-3sqrt3)/3)=tan^-1(-sqrt3) = -60^@$
In polar form $(r, θ); (6, - 60^{\circ})$ $(r,theta); (6, -60^@)$ [Ans]

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How do you convert $(3, - 3 \sqrt{3})$ $(3, -3sqrt3)$ to polar form?

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