How do you convert $(3, - 4)$ $(3,-4)$ to polar form?

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How do you convert $(3, - 4)$ $(3,-4)$ to polar form?

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Answer 1 · 2017-11-26T11:46:15

$(5, - 0.927)$ $(5,-0.927)$

Explanation:

$to convert from cartesian to polar form$ $"to convert from "color(blue)"cartesian to polar form"$

$that is (x, y) \to (r, θ) with$ $"that is "(x,y)to(r,theta)" with"$

$∙ x r = \sqrt{x^{2} + y^{2}}$ $•color(white)(x)r=sqrt(x^2+y^2)$

$∙ x θ = {tan}^{- 1} (\frac{y}{x})$ $•color(white)(x)theta=tan^-1(y/x)$

$here x = 3 and y = - 4$ $"here "x=3" and "y=-4$

$\Rightarrow r = \sqrt{3^{2} + {(- 4)}^{2}} = 5$ $rArrr=sqrt(3^2+(-4)^2)=5$

$θ = {tan}^{- 1} (\frac{- 4}{3}) = - 0.927 radians$ $theta=tan^-1((-4)/3)=-0.927" radians"$

$\Rightarrow (3, - 4) \to (5, - 0.927)$ $rArr(3,-4)to(5,-0.927)$

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How do you convert $(3, - 4)$ $(3,-4)$ to polar form?

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How do you convert (3,-4) (3,−4) (3,-4) to polar form?

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How do you convert $(3, - 4)$ $(3,-4)$ to polar form?