How do you convert $3 x - 2 y = 6$ $3x - 2y= 6$ into polar form?

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Answer 1 · 2015-11-24T05:17:00

$\Rightarrow r = \frac{6}{3 cos (θ) - 2 sin (θ)}$ $=> r = 6/(3cos(theta)-2sin(theta))$

When converting between polar and rectangular coordinates, we use the following equalities:
${(x = rcos(theta)), (y = rsin(theta)):}$

Substituting these into the equation,

$3x - 2y = 6$ becomes

$3rcos(theta) - 2rsin(theta) = 6$

$=> r(3cos(theta) - 2sin(theta)) = 6$

$=> r = 6/(3cos(theta)-2sin(theta))$

How do you convert 3x - 2y= 63x−2y=63x - 2y= 6 into polar form?