How do you convert #3y=2y^2-x^2 # into a polar equation?

Question

1105 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-10T04:33:25

#r = {3 sin theta} / { 2 sin ^2 theta - cos ^2 theta }#

#x = r cos theta #

#y = r sin theta #

#3 y = 2y^2 - x^2#

#3 r sin theta = 2 r^2 sin ^2 theta - r ^2 cos ^2 theta#

#3 sin theta = r(2 sin ^2 theta - cos ^2 theta)#

#r = {3 sin theta} / { 2 sin ^2 theta - cos ^2 theta }#

We stop here.