How do you convert $4 x^{2} y = 1$ $4x^2y=1$ into polar form?

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Answer 1 · 2016-01-26T00:18:54

Use these two identities ...

$x = r cos θ$ $x=rcostheta$
$y = r sin θ$ $y=rsintheta$

Now use those identities by substitution into the original equation ...

$4 x^{2} y = 1$ $4x^2y=1$

$4 {(r cos θ)}^{2} (r sin θ) = 1$ $4(rcostheta)^2(rsintheta)=1$

Simplify ...

$r = {(4 {cos}^{2} θ sin θ)}^{- \frac{1}{3}}$ $r=(4cos^2thetasintheta)^(-1/3)$

hope that helped

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