How do you convert $4x+3y-8=0$ into slope intercept form?

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Answer 1 · 2015-04-02T20:01:09

The slope-intercept form is
$y=mx+b$ for some constant values $m$ (the slope) and $b$ the y-intercept.

$4x+3y - 8 = 0$
is equivalent to
$3y = -4x + 8$

By dividing both sides by $3$ we get
$y = -4/3 x +8/3$

So the slope is $(-4/3)$ and the Y-intercept is at $(0,8/3)$

How do you convert 4x+3y-8=04x+3y-8=0 into slope intercept form?