How do you convert $4 x - y + 3 = 0$ $4x - y + 3 = 0$ to polar form?

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How do you convert $4 x - y + 3 = 0$ $4x - y + 3 = 0$ to polar form?

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Answer 1 · 2016-08-02T14:57:52

$r = \frac{- 3}{4 cos θ - sin θ}$ $r=(-3)/(4costheta-sintheta)$

Explanation:

To convert from $cartesian to polar form$ $color(blue)"cartesian to polar form"$

$Reminder$ $color(orange)"Reminder"$

$color(red)(|bar(ul(color(white)(a/a)color(black)(x=rcostheta , y=rsintheta)color(white)(a/a)|)))$
Substitute these values into given equation.

$rArr4(rcostheta)-(rsintheta)+3=0$

$rArr4rcostheta-rsintheta+3=0$

$rArrr(4costheta-sintheta)=-3$

$rArrr=(-3)/(4costheta-sintheta)$

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How do you convert $4 x - y + 3 = 0$ $4x - y + 3 = 0$ to polar form?

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