How do you convert $4 y^{2} = x$ $4y^2 = x$ into polar form?

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Answer 1 · 2018-04-23T03:27:50

$4 r {sin}^{2} θ = cos θ$ $4r sin^2 theta = cos theta$

Substitute $x = r cos θ$ $x = r cos theta$ and $y = r sin θ$ $y = r sin theta$

$4 r^{2} {sin}^{2} θ = r cos θ$ $4 r^2 sin ^2 theta = r cos theta$

$4 r {sin}^{2} θ = cos θ$ $4r sin^2 theta = cos theta$

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How do you convert 4y^2 = x4y2=x4y^2 = x into polar form?