How do you convert (6,9)(6,9) to polar form?

1 Answer
Jim G.
May 18, 2016

(sqrt117 ,0.983)(√117,0.983)

Explanation:

Using the formulae that links Cartesian and Polar coordinates.

•r=sqrt(x^2+y^2)∙r=√x2+y2

•theta=tan^-1(y/x)∙θ=tan−1(yx)

here x = 6 and y = 9 : Substitute these values into the formulae.

rArrr=sqrt(6^2+9^2)=sqrt117" in simplest form"⇒r=√62+92=√117 in simplest form

and theta=tan^-1(9/6)=0.983" radians"θ=tan−1(96)=0.983 radians

rArr(r,theta)=(sqrt117,0.983)=(sqrt117,56.3^@)⇒(r,θ)=(√117,0.983)=(√117,56.3∘)

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