How do you convert $θ = 6π$ into cartesian form?

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Answer 1 · 2016-07-01T06:52:15

$x>=0 and y=0$ . These represent x-axis in the x-positive direction

Only r varies in the direction $theta=6pi$ , which is same as

$theta=0, along the initial line$ ..

Now, $x= r cos theta= r cos 6pi=r(1)=r>=0$

#y=r sin theta= r sin 6pi=r(0)=0...

How do you convert θ = 6πθ = 6π into cartesian form?